OBSSCircuit DescriptionV1.1010/02/94 20:07 CET.Component & analysis parameters of a circuit.TINA 6.01.001SF [Beta #009]B(c) Copyright 1993,94,95,96 DesignSoft Inc. All rights reserved.7 $Circuit$?>6@6 Arial DThe \i(i,s)(t) source current is sinusoidal, its amplitude is 5 A.DFind the amplitude of the current of the inductor and the resistor!Symbol????@3333??@ Arial$\d(#Interpreter)!{Solution by TINA's Interpreter}om:=2*pi*1000;is:=5;iL:=is*R/(R+j*om*L);iL=[1.8022-2.4007*j]iR:=is*j*om*L/(R+j*om*L);iR= abs(iL)=radtodeg(arc(iL))= abs(iR)=radtodeg(arc(iR))=\d( )\d( @ Configuration begin )\d( ; numerical format )\d( 0 )\d( 1 )\d( 0 )\d( 1 )\d( 4 ) \d( ; math )\d( 1.00000000000000E-0002 ) \d( 100 )\d( 2.00000000000000E-0005 ) \d( 100 )\d( ; drawing )\d( 0 )\d( s )\d( V )\d( t )\d( U )\d( )\d( 0.00000000000000E+0000 )\d( 2.00000000000000E-0005 ) \d( 100 )\d( .@ Configuration end )Symbol????@3333??!!!((!((#2@is#2@(iL#2@iR 2tR? A? 2l( LrQ-" ? A2d is(t)@@@25(,?*@D@ư>?&?Y@[dd??.A.A.AeAMbP?@@?Mb`?ư>" 4@D@ =B?& .>??ư>ư>ư>ư>ư>ư>?I@?I@?I@;@ư>-q=ư>MbP?-q=MbP?vIh%<=Y@D@-C6??MbP?$@?{Gz?@??+= _BKH9$@Y@#B ;MbP?ҶOɃ;?Xd I@