OBSSCircuit DescriptionV1.1010/02/94 20:07 CET.Component & analysis parameters of a circuit.TINA 6.01.001SF [Beta #009]B(c) Copyright 1993,94,95,96 DesignSoft Inc. All rights reserved.7 $Circuit$?R@R ArialASymbol????@3333??U@U ArialBSymbol????@3333??G5.@5. Arial *Find the Norton equivalent of the network2for the points A and B at a frequency: f = 1 kHz!0\i(V,max)= 10 V. (The circuit of the example 1)Symbol????@3333??B@B ArialASymbol????@3333??Eb@Eb ArialBSymbol????@3333??$@$ ArialASymbol????@3333??j@j ArialBSymbol????@3333??L@ Arial)\d(#Interpreter)!{Solution by TINA's Interpreter}VM:=10;f:=1000;om:=2*pi*f;Z1:=R1+j*om*L;Z2:=R2/(1+j*om*C*R2); IN:=VM/Z1;IN=[0.004-0.0042*j]abs(IN)=[0.0058]radtodeg(arc(IN))=[-46.3207]abs(IN)/sqrt(2)=[0.0041]/ZN:=Replus((R1+j*om*L),replus(R2,(1/j/om/C)));ZN=[301.7035-303.4914*j]abs(ZN)=[427.9393]radtodeg(arc(ZN))=[-45.1693]CN:=-1/im(ZN)/om;CN=[524.4134n]\d( )\d( @ Configuration begin )\d( ; numerical format )\d( 1 )\d( 1 )\d( 0 )\d( 1 )\d( 4 ) \d( ; math )\d( 1.00000000000000E-0002 ) \d( 100 )\d( 2.00000000000000E-0005 ) \d( 100 )\d( ; drawing )\d( 0 )\d( s )\d( V )\d( t )\d( U )\d( )\d( 0.00000000000000E+0000 )\d( 2.00000000000000E-0005 ) \d( 100 )\d( .@ Configuration end )Symbol????333333??!  !!  !XX!!!pXpX!` ` !` ` !8888!````!````)`8``8H8H``!8888!8888!P88P88!P``P``!@@@@!`hh`hh!hhhh!h`hh`h!H@(@H@(@!@p@@p@!@@@@!@@@@!hhhh 2u R2@ A? 2m CBY[%> A.A2dX $vs(t)$@@@ 2lL? A 2upR1@ A? 2u` R2@ A? 2m` CBY[%> A.A 2l8L? A 2u`8R1@ A?c2HP8 ZN@@ 2uh R2@ A? 2mh CBY[%> A.A2d@ $vs(t)$@@@ 2lH@L? A 2u@R1@ A?#2@@ IN2525`25`h,?*@D@ư>?&dd?Y@[dddd$@?.A.A.AeAMbP?@@?ư>ư> " 4@D@ =B?& .>??ư>ư>ư>ư>ư>ư>?I@?I@?I@;@ư>-q=ư>MbP?-q=MbP?vIh%<=Y@D@-C6??MbP?4@?{Gz?@??+= _BKH9$@Y@#B ;ư>ҶOɃ;?Xd I@