OBSSCircuit DescriptionV1.1010/02/94 20:07 CET.Component & analysis parameters of a circuit.TINA 6.00.022SF [Beta #009]B(c) Copyright 1993,94,95,96 DesignSoft Inc. All rights reserved.7 $Circuit$?&(@( Arial [Find the average and the reactive powers of the two-pole connected to the current source !Find its p(t), too !Symbol????@3333??]@] Arial  \i(i,s)(t)=(100 * cos\s(w) t)mA\s(w) = 1 krad/sSymbol????@3333??R@D@@D ArialP = 12.5 mW, Q = - 12.5 mvar,6p(t) = [12.5 + 17.68 * cos (2 * \s(w) * t + 45)] mW,Cp(t) = [12.5 * (1 + cos 2 * \s(w) * t) - 12.5 * sin \s(w) * t] mW.Symbol????@3333??F@F Arial  Solution.Symbol????@3333??X0@0 Arial$\d(#Interpreter)"{Solution by TINA's Interpreter!} om:=1000; Is:=0.1;!V:=Is*(1/(1/R+j*om*C+1/j/om/L));V= S:=V*Is/2; P:=Re(S); Q:=Im(S);P=Q=abs(S)=\d( )\d( @ Configuration begin )\d( ; numerical format )\d( 0 )\d( 1 )\d( 0 )\d( 1 )\d( 4 ) \d( ; math )\d( 1.00000000000000E-0002 ) \d( 100 )\d( 2.00000000000000E-0005 ) \d( 100 )\d( ; drawing )\d( 0 )\d( s )\d( V )\d( t )\d( U )\d( )\d( 0.00000000000000E+0000 )\d( 2.00000000000000E-0005 ) \d( 100 )\d( .@ Configuration end )Symbol????@3333??!PP!PP!!%!!2dis(t)?Dc@2>P 2tR@ A? 2m2CMb0? A.A 2lP 3L{Gz? A25&*@D@Tư>?&?Y@[dd??.A.A.AeAMbP?@@?ư>ư>" 4@D@ =B?& .>??ư>ư>ư>ư>ư>ư>?I@?I@?I@;@ư>-q=ư>MbP?-q=MbP?vIh%<=Y@D@-C6??MbP?$@?{Gz?@??+= _BKH9$@Y@#B ;MbP?ҶOɃ;?Xd I@