OBSSCircuit DescriptionV1.1010/02/94 20:07 CET.Component & analysis parameters of a circuit.TINA 6.00.022SF [Beta #009]B(c) Copyright 1993,94,95,96 DesignSoft Inc. All rights reserved.7 $Circuit$?}<.@<. Arial BFind the absorbed average and reactive powers of the resistor andGcapacitor and the produced average and reactive powers of the source !9Check if the produced and absorbed powers are balanced !Symbol????@3333??%@% Arial R = 1 kohmC = 1 \s(m) FSymbol????@3333??{@ Arial%\d(#Interpreter)"{Solution by TINA's Interpreter!} om:=2000*pi;V:=10;I:=V/(R+1/j/om/C);Iaq:=sqr(abs(I)); PR:=Iaq*R/2;PR=QC:=Iaq/om/C/2;QC=Ic:=Re(I)-j*Im(I); Sv:=-V*Ic/2;Sv=\d( )\d( @ Configuration begin )\d( ; numerical format )\d( 0 )\d( 1 )\d( 0 )\d( 1 )\d( 4 ) \d( ; math )\d( 1.00000000000000E-0002 ) \d( 100 )\d( 2.00000000000000E-0005 ) \d( 100 )\d( ; drawing )\d( 0 )\d( s )\d( V )\d( t )\d( U )\d( )\d( 0.00000000000000E+0000 )\d( 2.00000000000000E-0005 ) \d( 100 )\d( .@ Configuration end )Symbol????@3333??!%pp%!%%p p  %HpHHp 2tR@@ A?2? PR 2m CHz> A.A2?pPC2j M 10V/0/1kHz$@@@2? BPv2=HB2=C2=A2=pA2=B2= 0C2=D2= D25&*@D@Tư>?&?Y@[dd??.A.A.AeAMbP?@@?ư>ư>" 4@D@ =B?& .>??ư>ư>ư>ư>ư>ư>?I@?I@?I@;@ư>-q=ư>MbP?-q=MbP?vIh%<=Y@D@-C6??MbP?$@?{Gz?@??+= _BKH9$@Y@#B ;MbP?ҶOɃ;?Xd I@