OBSSCircuit DescriptionV1.1010/02/94 20:07 CET.Component & analysis parameters of a circuit.TINA 6.01.001SF [Beta #009]B(c) Copyright 1993,94,95,96 DesignSoft Inc. All rights reserved.7 $Circuit$?t@ Arial RThe peak value of phase voltages in a three-phase balanced Y-connected generator ]is 100 V. The generator is loaded by a triangle-connected three-pole of the same impedances )C = 10 \s(m)F, R = 100 \s(W), f = 50 Hz.@Find the time functions of a.) the phase voltages of the loadO b.) the phase currents of the loadC c.) the line currents.Symbol????333333??J-@- Arial3\d(#Interpreter)7{Solution by TINA's Interpreter. Since the symmetry we9calculate only one phase. The phase voltage of the load .equals to the line voltage of the generator.}f:=50; om:=2*pi*f;VL:=sqrt(3)*100;VL=[173.2051]I1p:=VL/R1+VL*j*om*C1;I1p=[1.7321E0+5.4414E-1*j]I1p:=I1p*exp(j*pi/6);I1p=[1.2279E0+1.3373E0*j]abs(I1p)=[1.8155]radtodeg(arc(I1p))=[47.4406]I2p:=I1p*exp(-j*2*pi/3);I2p=[5.4414E-1-1.7321E0*j]abs(I2p)=[1.8155]radtodeg(arc(I2p))=[-72.5594]I3p:=I1p*exp(j*pi/6);abs(I3p)=[1.8155] Ib:=I2p-I1p;abs(Ib)=[3.1446]radtodeg(arc(Ib))=[-102.5594]\d( )\d( @ Configuration begin )\d( ; numerical format )\d( 0 )\d( 1 )\d( 0 )\d( 1 )\d( 4 ) \d( ; math )\d( 1.00000000000000E-0002 ) \d( 100 )\d( 2.00000000000000E-0005 ) \d( 100 )\d( ; drawing )\d( 0 )\d( s )\d( V )\d( t )\d( U )\d( )\d( 0.00000000000000E+0000 )\d( 2.00000000000000E-0005 ) \d( 100 )\d( .@ Configuration end )Symbol????333333??%PXP(PXPXP(!%)!XXXX!0X0`0X0`%XX!(X(X!XPXXPX!P(PXP(PX!x(P(x(P(!((((!8X8X!%000!!hXhX!!#2@0`ic#2@ia#2@X0ib"2Av1L"2Ahv2L2uP(R1Y@ A?2ux(/R2Y@ A?2u( R3Y@ A?2n0C1h㈵> A.A252502n8C3h㈵> A.A2525(2nPXUC2h㈵> A.A2a0v2Y@I@^2a0)v1Y@I@2a0Fv3Y@I@^@"2A v3L250,?*@D@ư>?&?Y@[dd??.A.A.AeA{Gz?i@?ư>ư>" 4@D@ =B?& .>??ư>ư>ư>ư>ư>ư>?I@?I@?I@;@ư>-q=ư>MbP?-q=MbP?vIh%<=Y@D@-C6??MbP?$@?{Gz?@??+= _BKH9$@Y@#B ;MbP?ҶOɃ;?Xd I@