BRIDGE NETWORKS
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1.
DC
BRIDGE NETWORKS
The
DC bridge is an electrical circuit for the precise measurement of resistances.
The best known bridge circuit is the Wheatstone bridge, named after Sir Charles
Wheatstone (1802
– 1875),
an
English
physicist and inventor.
The Wheatstone
bridge circuit is shown in the figure below. The interesting feature of this
circuit is that if the proyducts of the opposite resistances (R1R4 and R2R3) are
equal, the current and voltage of the middle branch is zero, and we say that the
bridge is balanced. If three of the four resistors (R1, R2, R3, R4) are known,
we can determine the resistance of the fourth resistor. In practice the three
calibrated resistors are adjusted until the voltmeter or ammeter in the middle
branch reads zero.

Let’s
prove the condition of balance.
When
in balance, the voltages on R1 and R3 must be equal:
therefore
R1
R3+R1 R4 = R1 R3 +
R2 R3
Since
the term R1 R3 appears on both sides of the equation, it
can be subtracted and we get the condition of balance:
R1
R4 = R2 R3
In
TINA you can simulate balancing the bridge by assigning hotkeys to the
components to be changed. To do this, double click on a component and assign a
hotkey. Use a function key with the arrows or a capital letter, e.g. A to
increase and another letter, e.g. S to decrease the value and an increment of
say 1. Now when the program is in interactive mode, (the DC button is pressed)
you can change the values of the components with their corresponding hotkeys.
You can also double-click on any component and use the arrows on the right side
of the dialog below to change the value.

Example
Find
the value of Rx if the Wheatstone-bridge is balanced. R1
= 5 ohm, R2 = 8 ohm,
R3
= 10 ohm.

The
rule for Rx
Checking
with TINA:
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If
you have loaded this circuit file, press the DC button and hit the A key a few
times to balance the bridge and see the corresponding values.
2.
AC
BRIDGE NETWORKS
The same technique
can also be used for AC circuits, simply by using impedances instead of
resistances:
In this case, when
Z1
Z4
= Z2 Z3
the
bridge will be balanced.
If
the bridge is balanced and for example Z1, Z2
, Z3 are known
Z4
= Z2 Z3
/ Z1
Using an AC bridge,
you can measure not only impedance, but also resistance, capacitance,
inductance, and even frequency.
Since
equations containing complex quantities mean two real equations (for the
absolute values and phases or real and imaginary
parts) balancing an AC circuit
normally needs two operating buttons but also two quantities can be
simultaneously found by balancing an AC bridge. Interestingly
the balance condition of many AC bridges are independent of the
frequency. In the following we will introduce the most well known bridges, each
named after their inventor(s).
Schering
– bridge: measuring capacitors with series loss.

The
bridge will be balanced if:
Z1
Z4
= Z2 Z3
In
our case:
after
multiplication:
The
equation will be satisfied if both real and imaginary parts are equal.
In
our the bridge, only C and Rx are unknown. To find them we have to
change different elements of the bridge. The best solution is to change R4
and C4 for fine-tuning, and R2 and C3 to set
the measurement range.
Numerically
in our case:
independent of the frequency.
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At the calculated values the current equals zero.
Maxwell
bridge: measuring capacitors with parallel loss
Find
the value of the capacitor C1 and its parallel loss R1 if
the frequency f = 159 Hz.
The
condition of balance:
Z1Z4
= Z2Z3

For
this case:
The
real and imaginary parts after multiplication:
R1*R4
+ j w
L1*R1 = R2*R3 + j w
R1 R2 R3C1
And from here the
condition of balance:
Numerically
R1 = 103*103/103 = 1 kohm,
C1 = 10-3/106 = 1 nF
In
the next figure you can see that with these value of C1 and R1
the current really is zero.
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Hay bridge:
measuring inductances with series loss
Measure
the inductance L1 with series loss R4.
The
bridge is balanced if
Z1Z4
= Z2Z3
After multiplying,
the real and imaginary parts are:
Solve
the second equation for R4, substitute it into the first criteria,
solve for L1, and substitute it into the expression for R4:
These
criteria are frequency dependent; they are valid only for one frequency!

Numerically:
| Using
the interpreter: om:=Vsw L:=C1*R2*R3/(1+om*om*C1*C1*R1*R1) R:=om*om*R1*R2*R3*C1*C1/(1+om*om*C1*C1*R1*R1) L=[5.94070853] R=[59.2914717] |
Checking
the result with TINA:
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Wien-Robinson
bridge: measuring frequency
How
can you measure frequency with a bridge?
Find the conditions for balance in the Wien-Robinson bridge.

The
bridge is balanced if R4
ּ(R1 + 1/ j w
C1 ) = R2 ּR3 / (1 + j
w
C3 R3)
After
multiplication and from the requirement of equality of the real and imaginary
parts:
If C1 = C3 = C and R1
= R3 = R the bridge will
be balanced if R2 = 2R4
and the angular frequency:
`
Checking the result
with TINA:
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